Ask Question
30 March, 02:40

The half-life of 222Rn is approximately 4 days. A sealed vessel is found to contain 1.5 mg of 222Rn. How much radon would have been present 12 days before this measurement was taken?

+4
Answers (1)
  1. 30 March, 03:09
    0
    In 12 days, 3 half-lives will have passed. Thus, the original amount will be:

    1.5 x 2³

    Original amount = 12 mg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The half-life of 222Rn is approximately 4 days. A sealed vessel is found to contain 1.5 mg of 222Rn. How much radon would have been present ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers