How many grams of MgCl, will be produced from 16.0 g of Mg (OH), and 11.0 g of HCl?

a) from Mg (OH) 2:

m MgCL2 = 26.121 g

b) from HCl:

m MgCl2 = 14.362 g

Explanation:

Mg (OH) 2 + 2HCl → MgCL2 + 2H2O

1 - Mg - 1

2 - Cl - 2

2 - O - 2

4 - H - 4

∴ Mw Mg (OH) 2 = 58.3197 g/mol

∴ Mw HCl = 36.46 g/mol

∴ Mw MgCl2 = 95.211 g/mol

from Mg (OH) 2:

⇒ m MgCL2 = (16.0 g Mg (OH) 2) (mol Mg (OH) 2/58.3197g) (mol MgCL2/mol Mg (OH) 2) (95.211 g MgCl2/mol MgCl2) = 26.121 g MgCl2

from HCl:

⇒ m MgCL2 = (11 g HCl) (mol HCl/36.46g) (mol MgCl2/2 mol HCl) (95.211 gMgCl2/mol MgCl2) = 14.362 g MgCl2