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Koen Park
Chemistry
24 November, 22:05
G (1) = 0 g (n) = g (n-1) + n g (2) =
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Gabrielle
24 November, 22:18
0
G (2) = 2
For this, you can plug in 2 everywhere you see an n. So the equation will read:
g (2) = g (2-1) + 2 - > g (2) = g (1) + 2. Since we are given g (1) = 0, we can plug in 0 where we see g (1). The equation is now. g (2) = 0+2. So, g (2) = 2.
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