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6 May, 16:24

For each strong acid solutions, determine [h3o+],[oh-], and ph. 0.28 m hcl

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  1. 6 May, 16:29
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    The given acid is HCl of 0.28 M which means that:

    [H+] = 0.28

    pH = - log[H+] = - log[0.28] = 0.5528

    pOH = 14 - pH

    pOH = 14 - 0.5528 = 13.447

    pOH = - log[OH-]

    log[OH-] = - 13.447

    [OH-] = 10^-13.447 = 3.5727*10^-14
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