For each strong acid solutions, determine [h3o+],[oh-], and ph. 0.28 m hcl

Question

Guest

Chemistry

6 May, 16:24

For each strong acid solutions, determine [h3o+],[oh-], and ph. 0.28 m hcl

+3

Answers (1)

Know the Answer?

Kobe West · Answer 1

The given acid is HCl of 0.28 M which means that:

[H+] = 0.28

pH = - log[H+] = - log[0.28] = 0.5528

pOH = 14 - pH

pOH = 14 - 0.5528 = 13.447

pOH = - log[OH-]

log[OH-] = - 13.447

[OH-] = 10^-13.447 = 3.5727*10^-14