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25 August, 02:38

How many milliliters of 0.550 m hydriodic acid are needed to react with 5.00 ml of 0.217 m csoh? hi (aq) + csoh (aq) → csi (aq) + h2o (l) ?

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  1. 25 August, 02:55
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    First calculate the moles of CsOH.

    moles CsOH = 0.217 M * 0.005 L = 0.001085 mol

    We need 1 mole of HI per 1 mole of CsOH, therefore the moles of HI needed is:

    moles HI = 0.001085 mol

    The volume required is therefore:

    Volume = 0.001085 mol / 0.550 M

    Volume = 1.97x10^-3 L = 1.97 mL
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