Calculate the number of grams of oxygen required to convert 23.0 g of glucose to CO2 and H2O.

Mr of C6H12O6 = (12*6) + (12*1) + (16*6) = 180

Mr of O2 = (16*2) = 32

If 180 g of glucose requires 6*32 g of oxygen

38 g of glucose would need 6*32/180 * 38=40.53 g of oxygen

ans=40.53

mr of CO2=44

If 180 g of glucose gives 44*6 g of CO2

therefore 38 g of it gives 44*6/180 * 38 = 55.73 g of CO2

I think that it equal to co=3 h=2 o=1