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21 June, 20:27

A solution contains 10.0 g pentane, C5H12, 20.0 g hexane, C6H14, and 10.0 g benzene, C6H6. What is the mole fraction of hexane?

A) 0.303

B) 0.471

C) 0.433

D) 0.362

E) 0.335

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  1. 21 June, 20:33
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    b) 0.47

    Explanation:

    MwC5H12 = 72.15g/mol

    ⇒mol C5H12 = (10.0) * (mol/72.15) = 0.1386molC5H12

    MwC6H14=86.18g/mol

    ⇒molC6H14 = (20.0) * (mol/86.18) = 0,232

    MwC6H6=78.11g/mol

    ⇒molC6H6 = (10.0) * (mol/78.11) = 0.128molC6H6

    XC6H14 = (0.232) / (0.1386+0.232+0,128) = 0.465≅0.47
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