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7 February, 06:15

Calculate the Ka for 0.220 M solution of H3AsO4, pH = 1.50

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  1. 7 February, 06:25
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    Remember that the formula to calculare KA is the following

    Ka = [H + ion]*[conj. base] / [acid]

    Now that you have the data you can do as the following:

    Ka = [H+]*[base] / [acid]

    Ka = [x]*[x] / [acid - x]

    Ka = x^2 / [acid - x]

    then we go

    Ka = [.032]^2 / [.220 -.032]

    Ka = 5.4 x 10^-3.

    Or what is the same

    Ka =.0054
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