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14 October, 22:32

What will be the n-factor for Ba (MnO4) 2 in acidic medium? (where it behaves as an oxidant)

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  1. 14 October, 22:55
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    Ba (MnO₄) ₂ → Ba²⁺ + 2MnO₄⁻

    MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O n=5
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