Ask Question
8 September, 23:38

What is the ph of a 4.8 m pyridine solution that has kb = 1.9 * 10-9? the equation for the dissociation of pyridine is?

+2
Answers (2)
  1. 8 September, 23:43
    0
    Answer: 9.98

    Explanation:

    1) The equation for the dissociation of pyridine is:

    C₅H₅N₅ (aq) + H₂O (l) ⇄ C₅H₅NH⁺ (aq) + OH⁻ (aq)

    2) Kb equation:

    Kb = [C₅H₅NH⁺ (aq) ] [OH⁻ (aq) ] / [C₅H₅N₅ (aq) ]

    Where:

    [C₅H₅NH⁺ (aq) ] = [OH⁻ (aq) ] ← from the equilibrium reaction

    [C₅H₅N₅ (aq) ] = 4.8 M ← from the statement

    ⇒ 1.9 * 10 ⁻⁹ = x² / 4.8 ⇒ x² = 9.12 * 10⁻⁹

    ⇒ x = 9.55 * 10⁻⁵ = [OH⁻ (aq) ]

    3) pOH

    pOH = - log [OH⁻ (aq) ] = 4.02

    4) pOH + pH = 14

    ⇒ pH = 14 - 4.02 = 9.98
  2. 8 September, 23:45
    0
    C5H5N (aq) + H2) ⇄C5H5NH + (aq) + OH - (aq)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the ph of a 4.8 m pyridine solution that has kb = 1.9 * 10-9? the equation for the dissociation of pyridine is? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers