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27 July, 22:33

If 14.8 moles of fe2o3 (s) and 8.93 moles of co (g) are allowed to react, and the percent yield is 56.6%, how many moles of fe3o4 (s) will actually be produced?

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  1. 27 July, 22:45
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    5,58 moles 3fe2o3+CO->2Fe3O4 + CO2

    14,8 14,8.56,6%.2/3

    why not use 8,93?

    If the percent yield is 100% and what is run out?

    14,8. then use it
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