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25 January, 03:28

A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock solution of sodium carbonate in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

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  1. 25 January, 03:31
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    The answer is 0.0698 M

    Explanation:

    The concentration was prepared by a serial dilution method.

    The formula for the preparation I M1V1 = M2V2

    M1 = the concentration of the stock solution = 0.171 M

    V1 = volume of the stock solution taken = 200 mL

    M2 = the concentration produced

    V2 = the volume of the solution produced = 940 mL

    Substitute these values in the formula

    0.171 * 200 = 490 * M2

    34.2 = 490 * M2

    Make M2 the subject of the formula

    M2 = 34.2/490

    M2 = 0.069795

    M2 = 0.0698 M (3 s. f)

    The concentration of the Chemist's working solution to 3 significant figures is 0.0698M
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