Give the theoretical yield, in moles, of CO2 from the reaction of 4.00 moles of C8H18 with 4.00 moles of O2. 2 C8H18 (l) + 25 O2 (

g. → 16 CO2 (

g. + 18 H2O (

g.

Question

Lizzy

Chemistry

15 July, 04:16

Give the theoretical yield, in moles, of CO2 from the reaction of 4.00 moles of C8H18 with 4.00 moles of O2. 2 C8H18 (l) + 25 O2 (

g. → 16 CO2 (

g. + 18 H2O (

g.

+3

Answers (1)

Know the Answer?

Mikayla Gross · Answer 1

2C₈H₁₈ + 25O₂ = 16CO₂ + 18H₂O

n (C₈H₁₈) = 4 mol

n (O₂) = 4 mol

C₈H₁₈:O₂=2:25 ⇒ 4:50 oxygen is the limiting reagent

n (CO₂) = 16n (O₂) / 25

n (CO₂) = 16*4/25=2.56 mol

Give the theoretical yield, in moles, of CO2 from the reaction of 4.00 moles of C8H18 with 4.00 moles of O2. 2 C8H18 (l) + 25 O2 (g. → 16 CO2 (g. + 18 H2O (g.

Give the theoretical yield, in moles, of CO2 from the reaction of 4.00 moles of C8H18 with 4.00 moles of O2. 2 C8H18 (l) + 25 O2 (

g. → 16 CO2 (

g. + 18 H2O (

g.