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27 April, 08:26

How many moles of MgSiO3 are in 233 g of the compound?

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  1. 27 April, 08:31
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    M = 233g

    M = 24 + 28 + 16 * 3 = 100g/mol

    n = m/M = 233g / 100 g/mol = 2,33mol
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