Calculate the mass of calcium carbonate present in a 50.00 mL sample of an aqueous calcium carbonate standard, assuming the standard is known to have a hardness of 75.0 ppm (hardness due to CaCO3). Also given is the density of the sample (0.9977g/mL) and the molar mass of CaCO3 (100.0g/mol).

Given the volume and density of the sample, we can calculate its mass.

mass = density * volume

mass = 0.9977 * 50

mass = 49.885 g

75 ppm Calcium Carbonate means that when there is 75 parts of Calcium Carbonate every one million parts of standard. Let one part be one gram.

So,

75 * 10⁻⁶ g CaCO₃ every gram of standard

grams of standard =.49.885

mass of CaCO₃ = 3.74 * 10⁻³ grams