A 0.43g sample of potassium hydrogen phthalate required 24.11cm³ NaOH for neutralization. Calculate the molarity of the NaOH

Molarity = 0.08 M

Explanation:

Given dа ta:

Volume of NaOH = 24.11 cm³ (24.11/1000 = 0.0241 L)

Mass of C₈H₅KO₄ = 0.43 g

Molarity of NaOH = ?

Solution:

First of all we will write the chemical equation:

C₈H₅KO₄ + NaOH → H₂O + KNaC₈H₄O₄

Number of moles of C₈H₅KO₄:

Number of moles = mass / molar mass

Number of moles = 0.43 g / 204.22 g/mol

Number of moles = 0.002 mol

Now we will compare the moles of C₈H₅KO₄ with NaOH.

C₈H₅KO₄; NaOH

1 : 1

0.002 : 0.002

Molarity of NaOH:

Molarity = number of moles / volume in litter

Molarity = 0.002 mol / 0.0241 L

Molarity = 0.08 M