What is the recommended way of preparing 100ml of 0.02M from 2M NaOH in the laboratory?

The recommended way of preparing 100ml of 0.02 M from 2M NaOH in the laboratory is to obey the equation V1S1=V2S2.

Explanation:

According to the given question

V2=100ml

S2=0.02M

S1 = 2M

Then V1=?

We all know that V1S1=V2S2

or V1=V2*S2:S1

or V1 = 100*0.02:2

or V1 = 1 ml

It can be concluded that 1ml of 2M NaOH solution and 99 ml distilled water should be mixed to prepare 100ml of 0.02 M NaOH solution.