8. If I have 34 grams of FeO, how many grams of Oxygen were synthesized?

Fe + O2 → Feo

34 gram of FeO produced 8 gram of oxygen.

Explanation:

Given dа ta:

Mass of FeO = 34 g

Mass of oxygen = ?

Solution;

Chemical equation:

2FeO → 2Fe + O₂

Number of moles of FeO:

Number of moles = mass / molar mass

Number of moles = 34 g / 71.8 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of FeO with oxygen:

FeO : O₂

2 : 1

0.5 : 1/2 * 0.5 = 0.25

Mass of oxygen:

Mass = number of moles * molar mass

Mass = 0.25 mol * 32 g/mol

Mass = 8 g

So 34 gram of FeO produced 8 gram of oxygen.