Consider the following gas samples: 10. g of hydrogen gas, 10. g of helium gas, 2.5 moles of nitrogen gas, 110. g of carbon dioxide gas, and 365 g of sulfur hexafluoride gas. Arrange the gas samples in order of increasing number of total atoms present.

Question

Josue Rollins

Chemistry

29 August, 13:54

Consider the following gas samples: 10. g of hydrogen gas, 10. g of helium gas, 2.5 moles of nitrogen gas, 110. g of carbon dioxide gas, and 365 g of sulfur hexafluoride gas. Arrange the gas samples in order of increasing number of total atoms present.

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Answers (1)

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Aldo Andersen · Answer 1

As we know,

One mole of a gas contains 6.023 * 10 ²³ number of atoms.

Moles is denoted by given mass divided by the molecular mass,

Hence,

n = w / m

n = moles,

w = given mass,

m = molecular mass.

(a) From the question,

w = 10 g,

As we know molecular mass of Hydrogen = 2 g/mol

Using the above formula, and putting the respective values,

Moles = n,

n = w / m = 10 / 2 = 5 mol

The number of atoms in one molecule of Hydrogen = 2

Hence,

The number of atoms = 5 * 2 * 6.023 * 10 ²³ = 60.23 * 10 ²³ atoms.

(b) From the question,

w = 10 g

As we know molecular mass of helium gas = 4 g/mol

Using the above formula, and putting the respective values,

Moles = n,

n = w / m = 10 / 4 = 2.5 mol

The number of atoms in one molecule of Helium = 1

Hence,

The number of atoms = 5 * 1 * 6.023 * 10 ²³ = 30.115 * 10 ²³ atoms.

(c) From the question,

moles of nitrogen gas = 2.5 mol

The number of atoms in one molecule of nitrogen gas = 2

Hence,

The number of atoms = 2.5 * 2 * 6.023 * 10 ²³ = 30.115 * 10 ²³ atoms.

(d) From the question,

w = 110 g

As we know molecular mass of carbon dioxide gas = 44 g/mol

Using the above formula, and putting the respective values,

Moles = n,

n = w / m = 110 / 44 = 2.5 mol

The number of atoms in one molecule of carbon dioxide = 3

Hence,

The number of atoms = 2.5 * 3 * 6.023 * 10 ²³ = 45.17 * 10 ²³ atoms.

(e)

From the question,

w = 365 g

As we know molecular mass of sulfur hexafluoride gas = 146 g/mol

Using the above formula, and putting the respective values,

Moles = n,

n = w / m = 365 / 146 = 2.5 mol.

The number of atoms in one molecule of sulfur hexafluoride gas = 7

Hence,

The number of atoms = 2.5 * 7 * 6.023 * 10 ²³ = 105.40 * 10 ²³ atoms.

Hence,

The order is -

sulfur hexafluoride > Hydrogen > carbon dioxide > nitrogen gas = helium gas