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1 June, 01:51

During an effusion experiment, oxygen gas passed through a tiny hole 2.5 times faster than the same number of moles of another gas under the same conditions. What is the molar mass of the unknown gas? (Note: the molar mass of oxygen gas is 32.0 g/mol.)

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  1. 1 June, 02:14
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    Use Law of Graham.

    rate A / rate B = √ (molar mass B / molar mass A)

    rate A / rate B = 2.5

    molar mass A = 32.0 g/mol

    => (molar mass B / molar mass A) = (rate A / rate B) ^2

    molar mass B = molar mass A * (rate A / rate B) ^2

    molar mass B = 32.0 g/mol * (2.5) ^2 = 200. g/mol

    Answer: 200 g/mol
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