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27 June, 05:55

A compound is analyzed and found to contain 22.10%Al, 25.40%P, and 52.50%O. What is the empirical formula of the compound?

A) Al (PO4) 3

B) Al4PO3

C) AlPO

D) AlPO4

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  1. 27 June, 06:13
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    A compound is analyzed and found to contain 22.10%Al, 25.40%P, and 52.50%O

    Let the total mass of compound = 100g

    The mass of Aluminum = 22.10 g

    Moles of Al = mass / atomic mass = 22.10 / 23 = 0.96

    The mass of P = 25.40 g

    Moles of P = 25.40 / 31 = 0.819

    The mass of oxygen = 52.50 g

    Moles of oxygen = 52.50 / 16 = 3.28

    The mole ratio of the two elements will be

    Al = 0.96/0.819 = 1.17

    P = 0.819/0.819 = 1

    O = 3.28 / 0.819 = 4

    The whole number ratio will be 1 : 1 : 4

    So formula will be AlPO4
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