Ask Question
24 December, 14:57

The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much time is required for 4.00 M PH3 to decrease to a concentration of 0.320 M?

+4
Answers (1)
  1. 24 December, 15:03
    0
    Answer: 588.8 seconds

    Explanation:

    1.00 - 0.25 = 0.75M

    4.00 - 0.320 = 3.68M

    Therefore,

    0.75M in 120 seconds

    3.68M in x seconds

    Cross multiply:

    0.75*x = 120*3.68

    x = 120*3.68/0.75

    x = 588.8 seconds
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much time is ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers