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13 December, 16:17

Determine the ph of a 0.00598 m hclo4 solution. 1.777 6.434 7.566 2.223 3.558

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  1. 13 December, 18:10
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    Answer: 2.223

    Explanation:

    HClO4, also known as perchloric acid, is a very strong. This means we can assume that complete dissociation occurs.

    This means that:

    [H+] = [HClO4] = 0.00598

    pH = - log[H+]

    pH = - log[ 0.00598] = 2.223

    Note: The base of the log is 10 (conventionally we don't write the base if it is 10)
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