A standard solution contained 0.842 g/L of solute. A student put 0.2mL of standard and 0.8mL water into a test tube. What is the new concentration in mg/mL? answer with 2 to 4 decimal places rounding correctly, without units.

Question

Kinsley Gould

Chemistry

4 July, 06:27

A standard solution contained 0.842 g/L of solute. A student put 0.2mL of standard and 0.8mL water into a test tube. What is the new concentration in mg/mL? answer with 2 to 4 decimal places rounding correctly, without units.

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Answers (1)

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Corinne Melendez · Answer 1

Answer is: new concentration is 0,168 mg/mL.

d (solution) = 0,842 g/L.

V (solution) = 0,2 mL = 0,0002 L.

V (water) = 0,8 mL.

V₁ (solution) = V (solution) + V (water).

V₁ (solution) = 0,8 mL + 0,2 mL = 1 mL.

m (solution) = 0,0002 L · 0,842 g/L · 1000.

m (solution) = 0,168 mg.

d₁ (solution) = m (solution) / V₁ (solution).

d₁ (solution) = 0,168 mg/mL.