A chemist wants to produce 12.00 grams of barium sulfate by reacting a. 6000 M BaCl2 solution with excess H2SO as show in the reaction below. What volume of the barium chloride should be used?

BaCl2 + H2SO4 - - > BaSO4 + 2HCl

Find the moles of BaSO4 first. Then since we know it's a one to one ratio from barium chloride to barium sulfate we can just solve for liters.

First you need to find the moles BaSO4, and the you will require to find barium sulfate in liters.

12.00gBaSO4 / 233.31 grams per mole

=.05141moles

Molarity=moles/liters

Hence,

Liters=.05141moles/.6Molarity

=.85 liters