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24 May, 15:00

A compound is composed of only C, H, and O. The combustion of a. 519-g sample of the compound yields 1.24 g of CO_2 and. 255 g of H_2O. What is the empirical formula of the compound?

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  1. 24 May, 15:05
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    Empirical formula is C₃H₃O.

    Explanation:

    Given dа ta:

    Mass of compound = 0.519 g

    Mass of CO₂ = 1.24 g

    Mass of H₂O = 0.255 g

    Empirical formula = ?

    Solution:

    %age of C, H, O

    C = 1.24 g/0.519 * 12/44 * 100 = 65.5%

    H = 0.255 g/0.519 * 2.016/18 * 100 = 5.6%

    O = 100 - (65.5+5.6)

    O = 28.9%

    Number of gram atoms of H = 5.6 / 1.01 = 5.5

    Number of gram atoms of O = 28.9 / 16 = 1.81

    Number of gram atoms of C = 65.5 / 12 = 5.5

    Atomic ratio:

    C : H : O

    5.5/1.81 : 5.5/1.81 : 1.81/1.81

    3 : 3 : 1

    C : H : O = 3 : 3 : 1

    Empirical formula is C₃H₃O.
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