How many moles of barium hydroxide, Ba (OH2), would be required to react with 117 g hydrogen bromide, HBr?

Question

Brando

Chemistry

31 May, 14:44

How many moles of barium hydroxide, Ba (OH2), would be required to react with 117 g hydrogen bromide, HBr?

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Answers (1)

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Jordyn Hooper · Answer 1

The moles of Ba (OH) 2 that is required to react with 117 HBr is calculated as below

find the moles of HBr used

mass / molar mass = 117 g / 80.9 g/mol = 1.446 moles

write the reacting equation

Ba (OH) 2 + 2 HBr = BaBr2 + 2 H2O

by use of mole ratio of Ba (OH) 2 : HBr which is 1:2 the moles of Ba (OH) 2 is therefore

= 1.446 moles x1/2 = 0.723 moles of Ba (OH) 2