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7 February, 17:22

Calculate the root mean square velocity of gaseous argon atoms at 26 ∘c.

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  1. 7 February, 17:23
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    By substitution in this formula:

    V = √3RTM

    when R = 8.31451 J. mol^-1K^-1

    T is the tempreture in K = 26 °C + 273 = 299 k

    M is the molar mass of argon Kg = 39.9 g = 39.9/1000 = 0.0399 Kg

    ∴V = √3*8.31451 * 299 / 0.0399

    ∴ V = 432 m/s
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