In the lab, frank has two solutions that contain alcohol and is mixing them with each other. he uses 100 milliliters less of solution a than solution

b. solution a is 13% alcohol and solution b is 17% alcohol. how many milliliters of solution b does he use, if the resulting mixture has 347 milliliters of pure alcohol?

Question

Blake Mccall

Chemistry

29 June, 11:53

In the lab, frank has two solutions that contain alcohol and is mixing them with each other. he uses 100 milliliters less of solution a than solution

b. solution a is 13% alcohol and solution b is 17% alcohol. how many milliliters of solution b does he use, if the resulting mixture has 347 milliliters of pure alcohol?

+5

Answers (1)

Know the Answer?

Jerome Ayala · Answer 1

Solution B (17% alcohol) = x ml

Solution A (13% alcohol) = (x-100) ml

0.17x ml alcohol in Solution B

0.13 (x-100) ml alcohol in Solution A

0.17x + 0.13 (x-100) = 347

0.17x+0.13x-13=347

0.3x = 360

x=360/0.3=3600/3=1200 ml solution B