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4 April, 13:54

Information related to a titration experiment is given in the balanced equation and table below.

H2SO4 (aq) + 2KOH (aq) → K2SO4 (aq) + 2H2O (2)

Titration Experiment Results

volume of H2SO4 (aq) used 12.0 mL

concentration of H, SO (aq)

volume of KOH (aq) used

36.0 mL

concentration of KO)

0.16 M

Based on the equation and the titration results, what is the concentration of the H2SO4 (aq) ?

1.

0.12 M

0.16 M

0.24 M

0.96 M

+4
Answers (1)
  1. 4 April, 14:20
    0
    0.24M

    Explanation:

    The equation for the reaction is given below:

    H2SO4 + 2KOH → K2SO4 + 2H2O

    From the equation above, we obtained the following information:

    nA (mole of acid) = 1

    nB (mole of base) = 2

    Data obtained from the question include:

    Va (volume of the acid) = 12mL

    Ca (concentration of the acid) = ?

    Vb (volume of the base) = 36mL

    Cb (concentration of the base) = 0.16 M

    The Ca (concentration of the acid) can be obtained as follow:

    CaVa/CbVb = nA/nB

    Ca x 12 / 0.16 x 36 = 1 / 2

    Cross multiply to express in linear form as shown below:

    Ca x 12 x 2 = 0.16 x 36

    Divide both side by 12 x 2

    Ca = 0.16 x 36 / 12 x 2

    Ca = 0.24M

    Therefore, the concentration of the acid is 0.24M
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