A concentration cell consists of two Sn/Sn2 + half-cells. The solution in one half-cell A is 0.13 M Sn (NO3) 2 and is 0.87 M Sn (NO3) 2 in the other half-cell B. Calculate the cell potential at 25 degrees C.

Question

Duncan Davies

Chemistry

14 May, 16:47

A concentration cell consists of two Sn/Sn2 + half-cells. The solution in one half-cell A is 0.13 M Sn (NO3) 2 and is 0.87 M Sn (NO3) 2 in the other half-cell B. Calculate the cell potential at 25 degrees C.

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Elsa Vincent · Answer 1

Base on your question where a concentration cell consist of two SN/SN2+half cells. The solution in one half cell A is 0.13M SN (NO3) 2 and is 0.87 M Sn (NO3) 2 in the other half cell to get the cell potential at 25 degree the answer is 0.059/2 log0.13/0.87