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2 February, 18:00

How many moles of NaOH will be required to produce 375.4 g of any Na2S04

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Answers (1)
  1. 2 February, 18:05
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    5.28 moles of NaOH.

    Explanation:

    Step 1:

    Determination of the number of mole in

    375.4 g of any Na2S04.

    Molar mass of Na2SO4 = (2x23) + 32 + (16x4) = 142g

    Mass of Na2SO4 = 375.4g

    Number of mole of Na2SO4 = ... ?

    Mole = Mass / Molar Mass

    Number of mole of Na2SO4 = 375.4/142 = 2.64 moles

    Step 2:

    The balanced equation for the reaction.

    H2SO4 + 2NaOH - > Na2SO4 + 2H2O

    Step 3:

    Determination of the number of mole of NaOH needed for the reaction.

    From the balanced equation above,

    2 moles of NaOH reacted to produce 1 mole of Na2SO4.

    Therefore, Xmol of NaOH will react to produce 2.64 moles of Na2SO4 i. e

    Xmol of NaOH = 2 x 2.64

    Xmol of NaOH = 5.28 moles

    Therefore, 5.28 moles of NaOH is needed for the reaction.
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