How many moles of chloride ions are in 0.2510 g of aluminum chloride?

Question

Guillermo Brandt

Chemistry

5 November, 20:22

How many moles of chloride ions are in 0.2510 g of aluminum chloride?

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Winston Bauer · Answer 1

1.882 x 10^ (-3) moles aluminum chloride has a formula of AlCl3. So let's calculate the molar mass of AlCl3 atomic mass of Al = 26.982 atomic mass of Cl = 35.453 molar mass of AlCl3 = 26.982 + 3 * 35.453 = 26.982 + 106.359 = 133.341 We have 0.2510 grams of AlCl3, so divide that by the molar mass of AlCl3, giving 0.2510 / 133.341 = 0.001882 moles = 1.882 x 10^ (-3) moles