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19 January, 07:52

What pressure is exerted by 932.3 g of CH4 in a 0.560 L steel container at 136.2 K?

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  1. 19 January, 08:21
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    Molar mass CH4 = 16.0 g/mol

    * number of moles:

    932.3 / 16 = > 58.26875 moles

    T = 136.2 K

    V = 0.560 L

    P = ?

    R = 0.082

    Use the clapeyron equation:

    P x V = n x R x T

    P x 0.560 = 58.26875 x 0.082 x 136.2

    P x 0.560 = 650.76

    P = 650.76 / 0.560

    P = 1162.07 atm
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