Which volume, in cm3, of 0.20 mol dm-3 naoh (aq) is needed to neutralize 0.050 mol of h2s (g) ? h2s (g) + 2naoh (aq) → na2s (aq) + 2h2o (l) ?

Question

Asher Morris

Chemistry

14 August, 06:11

Which volume, in cm3, of 0.20 mol dm-3 naoh (aq) is needed to neutralize 0.050 mol of h2s (g) ? h2s (g) + 2naoh (aq) → na2s (aq) + 2h2o (l) ?

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Answers (1)

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Dougherty · Answer 1

Answer is: volume of sodium hydroxide is 500 cm³.

Chemical reaction: H₂S + 2NaOH → Na₂S + 2H₂O.

From chemical reaction: n (H₂S) : n (NaOH) = 1 : 2.

n (NaOH) = 2 ·0.050 mol.

n (NaOH) = 0.1 mol.

V (NaOH) = n (NaOH) : c (NaOH).

V (NaOH) = 0.1 mol : 0.2 mol/dm³.

V (NaOH) = 0.5 dm³.

V (NaOH) = 0.5 dm³ · 1000 cm³/dm³.

V (NaOH) = 500 cm³.