A 0.100-g sample of your favorite candy is burned in a calorimeter that contains 1.00 kg of water initially at 21.0 ∘C. After the candy is burned, the water temperature is 34.5 ∘C. How many Calories are there per gram of your candy?

Answer: 565.245kJ

To answer this question, you need to know how much water heat capacity which was 4.187 kJ/kg K. First, we need to find the calorie absorbed by water. Since the sample is 1kg, the initial temperature is 21 ∘C and final temperature is 34.5 ∘C then the calculation would be:

Energy = (Final temp - initial temp) * heat capacity * mass

Energy = (34.5-21) ∘C * 4.187 * kJ/kg K * 1kg = 56.5245 kJ

The energy is made from 0.1 gram, then for 1 gram of energy it should be:

1 gram / 0.1gram x 56.5245 kJ = 565.245kJ