What mass (in g) of solute is contained in 764.9 mL of a 0.137 M solution of glucose, C6H12O6? Enter your answer with 3 significant figures and no units.

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Chemistry

3 March, 17:06

What mass (in g) of solute is contained in 764.9 mL of a 0.137 M solution of glucose, C6H12O6? Enter your answer with 3 significant figures and no units.

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Answers (1)

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Beatrice Mueller · Answer 1

18.9

Explanation:

Given data

Volume (V) : 764.9 mL = 0.7649 L Molar concentration (C) : 0.137 M = 0.137 mol/L

We can find the moles (n) of glucose using the following expression.

n = C * V

n = 0.137 mol/L * 0.7649 L

n = 0.105 mol

The molar mass of glucose is 180.16 g/mol. The mass corresponding to 0.105 moles is:

m = 0.105 mol * 180.16 g/mol = 18.9 g