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27 June, 23:29

helium gas in a 2.00 L cylinder is under 1.12 atm pressure. At 36.5°C that same gas sample has a pressure of 2.56 atm. What was the initial temperature of the gas in the cylinder?

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  1. 27 June, 23:43
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    T₁ = 135.41 K

    Explanation:

    Given dа ta:

    Initial pressure = 1.12 atm

    Finial temperature = 36.5 °C (36.5 + 273 = 309.5 K)

    Initial temperature = ?

    Final pressure = 2.56 atm

    Formula:

    P₁/T₁ = P₂/T₂

    P₁ = Initial pressure

    T₁ = Initial temperature

    P₂ = Final pressure

    T₂ = Final temperature

    Solution:

    P₁/T₁ = P₂/T₂

    T₁ = P₁T₂ / P₂

    T₁ = 1.12 atm * 309.5 K / 2.56 atm

    T₁ = 346.64 atm. K / 2.56 atm

    T₁ = 135.41 K
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