1.5 L of gas held under 1.0 atm, has the pressure increased to 303.9kPa, what is the new volume of the gas, if the temperature is held constant.

Answer: 1/2L

Explanation:

Volume and pressure are changed, so use Boyle's law.

P1V1=P2V2

Convert 303.9kpa to atm by mutiplying by (1/101.3) = 3atm

Plug in:

1.5 (1) = 3 (V2)

V2=1/2 L

This makes sense since volume and pressure are inversely proportional. The pressure is increased, so the volume must decrease.