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30 April, 14:41

For H 2 O, the H-O-H bond angle is 104.5 o and the measure dipole moment is 1.85 Debye. What is the magnitude of the O-H bond dipole moment for H 2 O? Estimate the bond angle in H 2 S given that the H-S bond dipole moment is 0.67 Debye and the resultant molecular dipole moment is 0.95 Debye.

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  1. 30 April, 15:09
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    Dipole moment of H₂O: 2.26 Debye

    Bond angle in H₂S: 89.7°

    Explanation:

    The total dipole moment (μr) for H₂O can be calculated by the sum of the dipole moments of each bond of O-H. Because the dipole moment is a vector, the sum of these vectors can be calculated by the cosine law.

    μr² = (μO-H) ² + (μO-H) ² + 2 * (μO-H) * (μO-H) * cos (104.5°)

    μr² = 1.85² + 1.85² + 2*1.85*1.85*cos (104.5°)

    μr² = 3.4225 + 3.4225 + 6.845 * (-0.2504)

    μr² = 5.13115

    μr = √5.13115

    μr = 2.26 Debye.

    For H₂S:

    0.95² = 0.67² + 0.67² + 2*0.67*0.67*cosθ

    0.9025 = 0.4489 + 0.4489 + 0.8978cosθ

    0.8978cosθ = 0.0047

    cosθ = 0.00523

    θ = arcos0.00523

    θ = 89.7°
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