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11 June, 23:42

Determine the molal concentration of 71.5 g of linoleic acid,

C12H3202, in 525 g of hexane, C6H14.

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  1. 12 June, 00:08
    0
    0.49 M

    Explanation:

    Given dа ta:

    Mass of solute = 71.5 g

    Mass of solvent = 525 g

    Molarity of solution = ?

    Solution:

    Number of moles of solute:

    Number of moles = 71.5 g / 280 g/mol

    Number of moles = 0.255 mol

    Now we will calculate the molarity:

    Molarity = number of moles of solute / litters of solution

    1 Kg = 1 L

    525 g * 1 kg / 1000 g

    0.525 kg or 0.525 L

    Molarity = 0.255 mol / 0.525 L

    Molarity = 0.49 M
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