Ask Question
26 March, 12:32

Mothballs are comprised primarily of naphthalene (C10H8). When 1.025 g of Naphthalene burns in a bomb calorimeter, the temperature rises from 24.25 degrees Celsius to 32.33 degrees Celsius. Find the change in energy for the combustion of a mole of naphthalene. The heat capacity of the bomb calorimeter is 5.11 kJ/degree Celsius.

+3
Answers (1)
  1. 26 March, 13:00
    0
    The change in energy for the combustion of a mole of naphthalene is 79 kJ

    Explanation:

    An excersise where you have to apply the Heat Capacity formula

    C = Q. ΔT

    where C is Heat Capacity and Q is Heat

    ΔT means (T° final - T° initial)

    5.11 kJ/°C = Q (32.33°C - 24.25°C)

    5.11 kJ/°C = Q (32.33°C - 24.25°C)

    5.11 kJ/°C = Q. 8.08°C

    5.11 kJ / 8.08°C = Q

    0.632 kJ = Q

    This heat is released by 1.025 grams of naphtalene.

    Molar mass Naphtalene : 128.17 g/m

    1.025 g / 128.17 g/m = 0.008 moles

    This are the moles, so we have to divide heat/moles to get the change in energy for one mole.

    0.632 kJ/0.008 mol = 79 kJ/m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Mothballs are comprised primarily of naphthalene (C10H8). When 1.025 g of Naphthalene burns in a bomb calorimeter, the temperature rises ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers