For the following metal and non-metal combination reaction you have 3 moles of Na. How many moles of Cl2 would you need to add to have stoichiometrically equivalent amounts of NA and Cl2?

2Na (s) + Cl2 (g) - - > 2NaCl (s)

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30 May, 12:36

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Deon Hahn · Answer 1

The molar ratio of Na : Cl₂ is 2:1

Moles of Na present = 3

2/1 = 3/x

x = 1.5

1.5 moles of Cl₂ needed to have stoichometrically equivalent amount

For the following metal and non-metal combination reaction you have 3 moles of Na. How many moles of Cl2 would you need to add to have stoichiometrically equivalent amounts of NA and Cl2?2Na (s) + Cl2 (g) - - > 2NaCl (s)