How many oxygen molecules are in 3.36 L of oxygen gas at STP

Question

Kaylee Mccann

Chemistry

8 February, 13:08

How many oxygen molecules are in 3.36 L of oxygen gas at STP

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Answers (1)

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Damarion Armstrong · Answer 1

Answer is: in 3.36 L of oxygen gas there is 0,15 mol (6 ·10²²) molecules of oxygen.

V (O₂) = 3,36 L.

Vm (O₂) = 22,4 L/mol.

n (O₂) = V (O₂) : Vm (O₂).

n (O₂) = 3,36 L : 22,4 L/mol.

n (O₂) = 0,15 mol.

N (O₂) = n (O₂) · Na.

N (O₂) = 0,15 mol · 6·10²³ 1/mol.

N (O₂) = 9 · 10 ²².

n - amount of substance.

Na - Avogadro number.