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21 November, 23:15

How many grams of magnesium bromide, MgBr2, must be dissolved to prepare 400. mL of a 0.183 M aqueous solution of the salt?

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  1. 21 November, 23:37
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    Answer: 13.47g of MgBr2

    Explanation:

    MM of MgBr2 = 24 + (2 x 80) = 24 + 160 = 184g/mol

    Mass conc. Of MgBr2 = 0.183 x184 = 33.672g

    33.672g of MgBr2 dissolves in 1000mL

    Therefore Xg of MgBr2 will dissolve in 400mL

    Xg of MgBr2 = (33.672 x 400) / 1000

    Xg of MgBr2 = 13.47g
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