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14 July, 23:31

If you had a mixture that was found to contain 1.05g SiO2, 0.69g Cellulose and 1.82g Calcium Carbonate. What percentage calcium carbonate is in the mixture?

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  1. 14 July, 23:50
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    (1.05+0.69+1.82) = 2.56g. %age of calcium carbonate is; (1.82/2.56) * 100 = 71%
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