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13 November, 12:15

Given the equations below, what is the total enthalpy change for the formation of phosphorus pentachloride, PCl5, when phosphorus is burned in excess chlorine?

P4 (s) + 6Cl2 (g) → 4PCl3 (g), ∆H = - 1224 kJ

4PCl3 (g) + 4Cl2 (g) → 4PCl5 (g), ∆H = - 372 kJ

P4 (s) + 10Cl2 (g) → 4PCl5 (g)

A. 852 kJ

B.-852 kJ

C.-1596 kJ

D. 1596 kJ

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