Given the equations below, what is the total enthalpy change for the formation of phosphorus pentachloride, PCl5, when phosphorus is burned in excess chlorine?
P4 (s) + 6Cl2 (g) → 4PCl3 (g), ∆H = - 1224 kJ
4PCl3 (g) + 4Cl2 (g) → 4PCl5 (g), ∆H = - 372 kJ
P4 (s) + 10Cl2 (g) → 4PCl5 (g)
A. 852 kJ
B.-852 kJ
C.-1596 kJ
D. 1596 kJ
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