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19 November, 05:23

If a gas in a closed container is pressurized from 15.2 atmospheres to 19.2 atmospheres and its original temperature was 25.0oC, what would the final temperature of the gas be?

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  1. 19 November, 05:52
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    From the gay lussac law which the pressure of a given amount of a gas held at constant volume is directly proportional to temperature in kelvin.

    that is p1/T1=P2/T2

    p1=15.2 atm

    P2=19.2 atm

    T1=25+273=298k

    T2=?

    15.2/298=19.2/T2

    5721.6=15.2 T2 divide both sides by 15.2

    therefore T2=376.4k or 103.4 degrees celsius
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