How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?

106.25 mL

Explanation:

For this, we can use

C1*V1=C2*V2

C1 = 0.45

V1 = 85

C2 = 0.20

V2=?

0.45 * 85 = 0.20 * V2

V2 = (0.45 * 85) / 0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 = 106.25mL