Ask Question
19 June, 00:34

9.87 g of calcium sulfate and 12.05 g of potassium react. What is the total amount of potassium sulfate that can be produced?

+4
Answers (1)
  1. 19 June, 01:00
    0
    Mass of K₂SO₄ = 12.633 g

    Explanation:

    The balance chemical equation for given reaction is as;

    CaSO₄ + 2 K = K₂SO₄ + Ca

    To solve this reaction one should first find the limiting reagent. To do so e will calculate the moles of each reactant as,

    Moles of CaSO₄ = Given Mass / M. Mass of CaSO₄

    Moles of CaSO₄ = 9.87 g / 136.14 g/mol

    Moles of CaSO₄ = 0.0725 moles

    Similarly for K,

    Moles of K = Given Mass / A. Mass of K

    Moles of K = 12.05 g / 39.10 g/mol

    Moles of K = 0.308 moles

    Now, according to equation,

    1 mole of CaSO₄ reacts with = 2 moles of K

    So,

    0.0725 moles of CaSO₄ will react with = X moles of K

    Solving for X,

    X = 0.0725 moles * 2 moles / 1 mole

    X = 0.145 moles of K

    As calculated above, we are provided with 0.308 moles of K while, we require only 0.145 moles of it so it means that K is in excess and CaSO₄ is the limiting reagent hence, CaSO₄ will control the yield of K₂SO₄.

    So,

    The amount of K₂SO₄ produced is calculated by first finding its moles as,

    According to equation,

    1 mole of CaSO₄ produced = 1 mole of K₂SO₄

    So,

    0.0725 moles of CaSO₄ will produce = X moles of K₂SO₄

    Solving for X,

    X = 0.0725 moles * 1 mole / 1 mole

    X = 0.0725 moles of K₂SO₄

    Now convert moles of K₂SO₄ to mass as,

    Mass of K₂SO₄ = Moles * M. Mass

    Mass of K₂SO₄ = 0.0725 * 174.26 g/mol

    Mass of K₂SO₄ = 12.633 g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “9.87 g of calcium sulfate and 12.05 g of potassium react. What is the total amount of potassium sulfate that can be produced? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers